bentuk sederhana dari √2/2-√8=​

[tex]\frac{\sqrt{2}}{2 - \sqrt{8}} = \frac{\sqrt{2}}{2 - \sqrt{4 \times 2}} = \frac{\sqrt{2}}{2 - 2 \sqrt{2}} [/tex]

Kemudian rasionalkan penyebutnya,

[tex]\frac{\sqrt{2}}{2 - 2 \sqrt{2}} = \frac{\sqrt{2}}{2 - 2 \sqrt{2}} \times \frac{2 + 2 \sqrt{2}}{2 + 2 \sqrt{2}} = \frac{(\sqrt{2})(2 + 2 \sqrt{2})}{(2 - 2 \sqrt{2})(2 + 2 \sqrt{2})} [/tex]

[tex]= \frac{2 \sqrt{2} + 2 \sqrt{4}}{4 + 4 \sqrt{2} - 4 \sqrt{2} - 4 \sqrt{4}} [/tex]

[tex]= \frac{2 \sqrt{2} + 2 \sqrt{4}}{4 - 4 \sqrt{4}}[/tex]

[tex]= \frac{2 \sqrt{2} + 2 \times 2}{4 - 4 \times 2} = \frac{2 \sqrt{2} + 4}{4 - 8} = \frac{2 \sqrt{2} + 4}{ - 4} = - \frac{\sqrt{2} + 2}{2} [/tex]

[answer.2.content]